What is slaking of lime?
(N/A) The addition of a limited amount of water to quicklime $(CaO)$ causes it to break into a powder,forming calcium hydroxide $(Ca(OH)_2)$. This process is known as slaking of lime. The chemical reaction is: $CaO(s) + H_2O(l) \rightarrow Ca(OH)_2(s)$.
Explore More
Similar Questions
$A$ metal $M$ readily forms its sulphate $MSO_4$ which is water-soluble. It forms its oxide $MO$ which becomes inert on heating. It forms its insoluble hydroxide $M(OH)_2$ which is soluble in $NaOH$ solution. Then $M$ is
MediumAIEEE 2002
View SolutionWhich of the following elements shows a high tendency to form peroxide?
Easy
View Solution$A$ chemistry student wants to identify the metal ion in a salt. They make a paste of the salt with concentrated $HCl$ on a clean platinum wire loop. If they take a small amount of this paste and place it in a non-luminous flame,it produces a green flame. Which metal is present?
Difficult
View SolutionMatch List-$I$ with List-$II$.
List-$I$ List-$II$ $a$. $Ca(OCl)_2$ $i$. Antacid $b$. $CaSO_4 \cdot \frac{1}{2} H_2O$ $ii$. Cement $c$. $CaO$ $iii$. Bleach $d$. $CaCO_3$ $iv$. Plaster of Paris
Choose the most appropriate answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $a$. $Ca(OCl)_2$ | $i$. Antacid |
| $b$. $CaSO_4 \cdot \frac{1}{2} H_2O$ | $ii$. Cement |
| $c$. $CaO$ | $iii$. Bleach |
| $d$. $CaCO_3$ | $iv$. Plaster of Paris |
Choose the most appropriate answer from the options given below:
Which of the following elements belongs to the $second$ group and $fifth$ period of the periodic table?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo